(4x+7)(x^2+3x-10)=0

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Solution for (4x+7)(x^2+3x-10)=0 equation:


Simplifying
(4x + 7)(x2 + 3x + -10) = 0

Reorder the terms:
(7 + 4x)(x2 + 3x + -10) = 0

Reorder the terms:
(7 + 4x)(-10 + 3x + x2) = 0

Multiply (7 + 4x) * (-10 + 3x + x2)
(7(-10 + 3x + x2) + 4x * (-10 + 3x + x2)) = 0
((-10 * 7 + 3x * 7 + x2 * 7) + 4x * (-10 + 3x + x2)) = 0
((-70 + 21x + 7x2) + 4x * (-10 + 3x + x2)) = 0
(-70 + 21x + 7x2 + (-10 * 4x + 3x * 4x + x2 * 4x)) = 0
(-70 + 21x + 7x2 + (-40x + 12x2 + 4x3)) = 0

Reorder the terms:
(-70 + 21x + -40x + 7x2 + 12x2 + 4x3) = 0

Combine like terms: 21x + -40x = -19x
(-70 + -19x + 7x2 + 12x2 + 4x3) = 0

Combine like terms: 7x2 + 12x2 = 19x2
(-70 + -19x + 19x2 + 4x3) = 0

Solving
-70 + -19x + 19x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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